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魏老师在《一类与三角形相似有关的开放型问题的一般结论》[1]中,结合特殊三角形性质,全等与相似的判定方法等知识,把问题进行拓展推广,得出了一般解法与结论,阅后颇有收获,但细细揣摩后,发现文中的拓展延伸问题条件多余,其结论也存在错误,特此提出商榷原题如下:(1)探究发现:如图1.△ABC与△DEF都是等腰直角三角形,∠ACB=∠EDF=90°,且点D在边AB上,AB与EF的中点都是点O,连接BF、CD、OC,当C、F、O在同一条直线上时,你发现BF与CD的数量关系是_________.
In the general conclusion of a kind of open-ended question about similarities with triangles [1], Wei Wei expanded and popularized the problems by combining the knowledge of special triangular nature, congruence and similar judging methods, and got the general solution Conclusion, after reading quite rewarding, but after careful examination, we found that the text of the conditions for the extension of the extension of the problem, the conclusion is also an error, hereby proposed the following questions: (1) found that: as shown in Figure 1. △ ABC and △ DEF are isosceles right-angled triangle, ∠ACB = ∠EDF = 90 °, and point D on the side AB, the midpoint of AB and EF are point O, connect BF, CD, OC, when C, F, O in On the same line, you find that the number of BFs and CDs is _________.