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编辑同志:我们在工作中发现了一个问题,由于水平有限,无法解决,特请教您们,您们一定会愿意帮助我们的。附表中所列数据为水质简分析结果报告,其中除K·+Na·由计算所得外,其他全部由试验计算所得。此水根据帕尔美耳分类属于第一级,为软水,仅有临时硬度,一般有硷金属的碳酸盐。根据我们的分析此水中有CO″_3存在。若有硷金属碳酸盐,则有负硬存在。但也有CaCO_3存在,这时CaCO_3就属于永硬,一般说负硬与永硬是不能并存的,但在这种情况下CaCO_3与Na_2CO_3是否能并存,如果能的话,那末,暂时硬度,永久硬度以及负硬到底如何确定。以上情况的出现是否是正常的,或由于我们做错了试验
Editor comrades: We found a problem in our work. Due to the limited level, we can’t solve it. We ask you to help you. You will be willing to help us. The data listed in the attached table is the water quality summary analysis report, except that K·+Na· is calculated and the rest is calculated by the test. This water belongs to the first class according to Palmier’s classification. It is soft water with only temporary hardness. It is generally carbonated with base metals. According to our analysis, there is CO′′_3 in the water. If there is a base metal carbonate, there is negative hardness. However, CaCO_3 is also present. At this time, CaCO_3 belongs to permanent hardness. In general, negative hardness and permanent hardness cannot coexist. But in this case, can CaCO_3 and Na_2CO_3 coexist, if so, then the temporary hardness, permanent hardness, and how to determine the negative hardness in the end, whether the above situation is normal, or because we did wrong test