一、题目原型2011年广东高考文理卷数学20题如下:设b>0,数列{an}满足a1=b,a1=b,an=nban1/(an1+n-1)(n≥2),1.求数列{an}的通项公式;2.证明:对于一切正整数n,2an≤bn-1+1。二、题目分析该题文理科考查的范围基本相同,题型也基本一样,都是分式型递推数列。但以往的题目从给出的条件入手都比较简 First, the title prototype 2011 Guangdong college entrance examination mathematics volume mathematics 20 questions are as follows: Let b> 0, the sequence {an} satisfy a1 = b, a1 = b, an = nban1 / (an1 + n-1) 1. Find the general formula of {an}; 2. Prove that for all positive integers n, 2an≤bn-1 + 1. Second, the topic analysis The subject of science exam basically the same range of questions are basically the same, are fractional recursive sequence. However, the previous questions from the conditions given are relatively simple