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关于sin x,cos x一次齐次的,型如a sin x ++bcosx=c(a≠0,b≠0)的三角方程,一股可用“引进輔角法”,“有理置換”或者用“乘方法”化原式为sin x或cos x的二次方程解出角x的通值式,如果运用解析几何的有关公式来求解就直覌得多,茲介紹两种解法如下: [解法1] 对照直綫的法綫式x cosω+y cosω--P=0,則三角方程a sin x+b cos x-c=0可以看成是过已知点P(b,a),与原点距离为c且直綫的法綫ON与x軸所成之角为x的一个直綫的方程。而这个三角方程的求解,实际上就是“已知直綫上一点
About the sin x, cos x one time homogeneous, type such as a sin x ++bcosx=c (a ≠ 0, b ≠ 0) trigonometric equation, one can use “introduction of auxiliary angle method”, “rational replacement” or The “multiplier method” solves the quadratic equation of the angle x with the original equation of sin x or cos x. If the analytical formula is used to solve the problem, the two solutions are described as follows: [solution] 1] The normal line of the control line x cos ω + y cos ω - P = 0, then the trigonometric equation a sin x + b cos xc = 0 can be seen as a known point P (b, a), and the distance from the origin is c. The equation of a straight line whose angle x formed by the straight line normal to the line x is x. And the solution of this trigonometric equation is actually "a point on the known straight line.