【摘 要】
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The paper proves that Lambek calculus with a De Morgan negation (LDN) is decidable which answers the open question in[9].Our proposal builds on the
【机 构】
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INSTITUTEOFLOGICANDCOGNITION,SUNYAT-SENUNIVERSITY
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The paper proves that Lambek calculus with a De Morgan negation (LDN) is decidable which answers the open question in[9].Our proposal builds on the embedding result from the conservative extension of LDN to the conservative extension of L with a minimal negation,and shows that the latter is decidable.
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