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For any integer n > 1, we prove that 2n(2n n)│n-1 Σ k=0(6k+1)(2k k)328(n-k-1)and2n(2n n) n-1 Σ k=0 (120k2+34k+3)(2k k) (4k 2k) 216(n-k-1).The first divisibility result confirms a conjecture of Z.-W.Sun.