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复合法由函数的定义运用复合的办法可求得函数解析式．例１已知ｆ（ｘ）＝５ｘ＋２，φ（ｘ）＝ｆ〔ｆ（ｘ）〕，求φ（ｘ）．解∵ｆ（ｘ）＝５ｘ＋２，∴φ（ｘ）＝ｆ〔ｆ（ｘ）〕＝ｆ（５ｘ＋２）＝５（５ｘ＋２）＋２＝２５ｘ＋１２．２凑合法已知ｆ〔φ（ｘ）〕＝ｔ（...
Compound method can be obtained by the use of complex methods defined by the function. Example 1 is known as f(x)=5x+2, φ(x)=f[f(x)] and φ(x). Solution f(x)=5x+2, ∴ ((x)=f[f(x)]=f(5x+2)=5(5x+2)+2=25x+12.2 It is legally known that f[φ(x)]=t (...