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根据C618车床走刀传动系统,走刀量大小是正比于车螺纹螺距大小,其比值大小可以根据传动关系求得(从略),也可以从铭牌上任意相对应的两个数值之比求得,即纵走刀量/螺距=0.28,则纵走刀量=0.28 ×螺距。要想车螺纹时兼车外圆其纵走刀量细化,就应该当手柄在Ⅱ时车螺纹,手柄在Ⅰ时车外圆,因为i_(倍1)/i_(倍2)=1/4,则纵走刀量/螺距=0.28/4=0.07,比值细化了则走刀量也细化了。可是在常用螺距1,1.25,1.5,1.75,2及2.5等在原铭牌上都规定手柄在位置Ⅰ时车螺距,所以纵走刀量就无法细化。这就
According to C618 lathe pass drive system, take the amount of the knife is proportional to the size of the thread pitch, the ratio of the size can be obtained according to the transmission relationship (omitted), can also be obtained from the nameplate any two corresponding to the ratio of the value obtained , That is, take the amount of vertical / pitch = 0.28, then take the amount of vertical knife = 0.28 × pitch. If you want to take the car thread and drive the wheel away from the length of its longitudinal cut amount of thinning, it should be when the handle in the Ⅱ car thread, the handle in the I car outer circle, because i_ (times 1) / i_ (times 2) = 1 / 4, then go vertical knife / pitch = 0.28 / 4 = 0.07, the ratio of thinning the amount of walking is also refined. However, the common thread pitch 1,1.25,1.5,1.75,2 and 2.5, etc. are provided on the original nameplate handle at the position I when the car pitch, so take the amount of vertical cut can not be refined. This is