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Fe_2(CO)_6(PhNCONPh)簇合物是由[Et_3NH][HFe_3(CO)_(11)]和C_6H_5NCO在苯中反应获得。应用四园衍射仪测定了该簇合物的晶体结构。晶体学数据:C_(19)H_(10)O_7N_2Fe_2,空间群P2_1/n,a=8.5062(1),b=13.2752(1),c=18.9038(2)(?),β=98.96(2)°,Z=4和D_c=1.643gcm~(-3)。结构系用直接法解出,最后R 因子为0.031.结果表明,题目簇合物分子是由苯代脲基C_6H_6—N—C(O)—N—C_6H_5中的N 原子,分别和(OC)_3Fe—Fe(CO)_3中的两个Fe 原子键合而成。使各两Fe 与N 原子和一个C 原子形成变形的双三角锥构型。
Fe_2 (CO) _6 (PhNCONPh) cluster was obtained by the reaction of [Et_3NH] [HFe_3 (CO) _ (11)] and C_6H_5NCO in benzene. The crystal structure of the cluster was determined by using four-garden diffractometer. The crystallographic data are as follows: C_ (19) H_ (10) O_7N_2Fe_2, space group P2_1 / n, a = 8.5062 1, b = 13.2752 1, c = 18.9038 2, °, Z = 4 and D_c = 1.643gcm ~ (-3). The structure was solved by the direct method, and the final R factor was 0.031. The results showed that the molecule of the title cluster consisted of N atoms in the phenylureido urea C_6H_6-N-C (O) -N-C_6H_5, _3 Fe-Fe (CO) _3 in the two Fe atoms bonded together. Double triangular pyramid configurations that deform each two Fe and N atoms and one C atom.