论文部分内容阅读
《义教本》在学习分式方程内容时有这样 一道例题:解关于x的方程:x+1/x=c+1/c,得 其解为x1=c,x2=1/c仔细观察、比较,此方程 很有特点,方程的左边是未知数与其倒数的和, 右边的形式与左边的形式完全相同,只是把未 知数换成了某个常数,而其解有两个,是这个常 数和它的倒数．这个结论简单易记,而且还可 以加以推广并应用． 例1 (2004年福建莆田的中考题):阅读 《义教本》在学习分式方程内容时有这样 一道例题:解关于x的方程:x+1/x=c+1/c,得 其解为x1=c,x2=1/c仔细观察、比较,此方程 很有特点,方程的左边是未知数与其倒数的和, 右边的形式与左边的形式完全相同,只是把未 知数换成了某个常数,而其解有两个,是这个常 数和它的倒数．这个结论简单易记,而且还可 以加以推广并应用． 例1 (2004年福建莆田的中考题):阅读
The book of Righteousness has such an example when studying the contents of fractional equations: solution to the equation of x: x+1/x=c+1/c, its solution is x1=c, and x2=1/c is carefully observed. In comparison, this equation is very characteristic. The left side of the equation is the sum of the unknown and its reciprocal. The form of the right side is exactly the same as the left side. It just replaces the unknown with a certain constant and its solution has two. This is the constant and it The countdown. This conclusion is easy to remember, but it can also be generalized and applied. Example 1 (In the examination of Putian, Fujian Province in 2004): When reading the “Righteous Teacher’s Book”, there is such an example when studying the content of the fractional equation: Solve the equation about x: x+1/x=c+1/c, get the solution For x1 = c, x2 = 1 / c carefully observe and compare, this equation is very characteristic, the left side of the equation is the sum of the unknown and its reciprocal, the right form is exactly the same as the left, but the unknown is replaced with a certain constant , and its solution has two, is this constant and its reciprocal. This conclusion is easy to remember, but it can also be generalized and applied. Example 1 (Chongqing Putian’s exam in 2004): Reading