高中物理(试用本)上册将圆锥摆作为圆周运动的一个特例作了重点介绍,并推导了圆锥摆摆角α与转动角速度ω之间的函数关系:cosα=g/lω~2。对于这个式子,有些人对它进行了如下讨论:当ω→∞时,因为g、l为恒量,所以g/lω~2→0,α→π/2,这说明要使摆球的摆角达到π/2是不可能的;当ω→0时,g/lω~2→∞。前一讨论无疑是正确的, In the high school physics (trial version) book, the conical pendulum was introduced as a special case of circular motion, and the functional relationship between the conical pendulum angle α and the rotational angular velocity ω was deduced: cosα=g/lω~2. For this equation, some people discuss it as follows: When ω → ∞, because g, l are constants, so g/lω~2→0, α→π/2, which explains the pendulum ball It is impossible for the angle to reach π/2; when ω→0, g/lω~2→∞. The previous discussion is undoubtedly correct.