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TaCl(NMe2)4(1)与Tp*K[Tp*=三(3,5-二甲基吡唑)硼化氢]的反应给出两个产物:第一个产物是Tp*Ta(NMe2)4(2),其中Tp*配体的一个N原子跟钽配位成键;第二种产物是[Tp*Ta(NMe2)4]·2Tp*K(3),其中[Tp*Ta(NMe2)4](2a)的Tp*配体的三个N原子跟钽配位成键.过量的化合物1加入化合物3中并没有跟其中的Tp*K反应.化合物2与氧气的进一步反应给出产物Tp*BH(NMe2)(4).通过类似的方法,化合物1与TpK[Tp=三(吡唑)硼化氢]的反应产出化合物TpTa(NMe2)4(5).研究了化合物3和5与氧气的反应.用核磁共振,元素分析和单晶X射线衍射对化合物2,4,和5进行了表征.
Reaction of TaCl (NMe2) 4 (1) with Tp * K [Tp * = tris (3,5-dimethylpyrazole) borohydride] gives two products: the first product is Tp * Ta ) 4 (2), where one N atom of the Tp * ligand coordinates with tantalum and the second product is [Tp * Ta (NMe2) 4] .2Tp * K The three N atoms of the Tp * ligand of NMe2) 4] (2a) coordinate to tantalum. The excess compound 1 is added to compound 3 and does not react with Tp * K. The further reaction of compound 2 with oxygen gives The product Tp * BH (NMe2) 4 (5) was obtained by a similar method to the reaction of compound 1 with TpK [Tp = tris 3 and 5 with oxygen The compounds 2, 4, and 5 were characterized by NMR, elemental analysis and single crystal X-ray diffraction.