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在束－气条件下，通过检测反应产物的化学发光光谱，研究了亚稳态Ｈｅ（２~３ｓ）原子与甲烷、氯代甲烷（ＣＨ_ｎＣｌ_（４－ｎ），ｎ＝１～３）反应中的解离激发动力学过程．观察到反应的主要激发态碎片ＣＨ（Ａ~２Δ）、ＣＨ（Ｂ~２Σ~（－））、ＣＨ（Ｃ~２Σ~＋）、Ｈ和ＣＣｌ（Ａ~２Δ），用参比反应测定了发光碎片的形成速率常数。对ＣＨ（Ａ，Ｂ）光谱的计算机模拟获得了ＣＨ（Ａ~２Δ，ｖ′＝０～２）和ＣＨ（Ｂ，ｖ′＝０）的振转分布。该反应的可资用能绝大部分转移成产物的平动能，且Ｈｅ（２~３ｓ）与甲烷及氯代甲烷反应形成ＣＨ（Ａ~２Δ，ｖ′＝０）的转动分布不同，前者为单Ｂｏｌｔｚｍａｎｎ分布，后者则在低转动能级上转动温度比高转动态低，近似可用双Ｂｏｌｔｚｍａｎｎ分布描述，对上述反应机理进行了讨论。
Under beam-gas conditions, the chemiluminescence spectra of the reaction products were used to study the reaction of metastable He (2 ~ 3s) with methane and methyl chloride (CH_nCl_ (4-n) The dissociation stimulates the kinetic process. The main excited fragment CH (A ~ 2Δ), CH (B ~ 2Σ ~), CH (C ~ 2Σ ~ +), H and CCl (A ~ 2Δ) were observed. Formation rate constant of luminescent debris. The vibrational distributions of CH (A ~ 2Δ, v ’= 0 ~ 2) and CH (B, v’ = 0) were obtained by computer simulation of CH (A, B) spectra. The kinetic energy of this reaction is mostly transferred to the translational energy of the product, and the rotational distribution of He (2 ~ 3s) and methane and methyl chloride react to form CH (A ~ 2Δ, v ’= 0) Single Boltzmann distribution, while the latter has a lower rotational temperature at low rotational energy levels than the high rotational state, which is approximated by the description of the double Boltzmann distribution, and the above reaction mechanism is discussed.