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已知当1＜a＜p＜∞时,有H*p=HSp=a Kp=Lp成立.一个自然的问题是H*1,HS1和L1之间的关系是什么?1970年,Davis证明了H*1=HS1.然而,到目前为止很少有关于H1和L1u之间关系的研究.在本文中,我们通过构造反例的方式说明H1(?)L1u,最终得到H1(?)L1u(?)L1.“,”As we have already known that when 1＜a＜p＜∞,H*p=HSp=a Kp=Lp.A natural question is that what the relations among H*1,HS1 and L1?In 1970,Davis proved that H*1=HS1.However,there are few researches on the relationship between H1 and L1u until now.In this paper,we prove that H1(?)L1u by constructing a counterexample and hence get H1(?)L1u(?)L1.