例1如图1所示,点A是反比例函数y=2/x(x>0)的图象上任意一点,AB∥x轴,交反比例函数y=3/x的图象于点B.以AB为边作?ABCD,其中C,D在x轴上,则?ABCD的面积S_(?ABCD)=.解从点A作AF⊥x轴于点F,从点B作BE⊥x轴于点E,则四边形ABEF为矩形,并且其面积为2+3=5.因为四边形ABCD为平行四边形, Example 1 As shown in Fig. 1, point A is an image at an arbitrary point on the inverse function γ = 2 / x (x> 0), AB∥x axis, and the image of the inverse proportion function y = 3 / x at point B. ABCD as ABCD, where C and D are on the x-axis, then the area of ​​ABCD is S AB AB =. The solution is made from point A to the AF ⊥ x axis at point F and from point B to BE ⊥ x axis At point E, the quadrilateral ABEF is a rectangle and its area is 2 + 3 = 5. Because the quadrilateral ABCD is a parallelogram,