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代入上式即得命题1.以下是命题1的几个等价命题.其中A,B∈R.命题2sin2A+sin2B+2sinAsinBcos(A+B)sin2(A+B)命题3cos2A+cos2B-2cosAcosBcos(A+B)=sin2(A+B)命题4sin2A+cos2B-2sinAcosBsin(A+B)=cos2(A+B);命题5cos’A+sin’B—ZcosAsinBsin(A+B)一。。S\A十B)
Substitution into the above formula is proposition 1. The following are several equivalent propositions of Proposition 1. Among them, A, B∈R. Proposition 2sin2A+sin2B+2sinAsinBcos(A+B)sin2(A+B) Proposition 3cos2A+cos2B-2cosAcosBcos(A+B)=sin2(A+B) Proposition 4sin2A+cos2B-2sinAcosBsin(A+B)=cos2(A+B); The proposition 5cos’A+sin’B-ZcosAsinBsin(A+B) one. . SA10B)