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代入上式即得命题1．以下是命题1的几个等价命题．其中A，B∈R．命题2sin2A+sin2B+2sinAsinBcos(A+B)sin2(A+B)命题3cos2A+cos2B-2cosAcosBcos(A+B)=sin2(A+B)命题4sin2A＋cos2B-2sinAcosBsin（A＋B）=cos2（A+B）；命题5cos’A＋sin’B—ZcosAsinBsin（A＋B）一。。S＼A十B）
Substitution into the above formula is proposition 1. The following are several equivalent propositions of Proposition 1. Among them, A, B∈R. Proposition 2sin2A+sin2B+2sinAsinBcos(A+B)sin2(A+B) Proposition 3cos2A+cos2B-2cosAcosBcos(A+B)=sin2(A+B) Proposition 4sin2A+cos2B-2sinAcosBsin(A+B)=cos2(A+B); The proposition 5cos’A+sin’B-ZcosAsinBsin(A+B) one. . SA10B)