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一、求值例1已知xy+z=a,yz+x=b,zx+y=c,求a1+a+b1+b+c1+c的值.解由已知可推出x+y+z≠0,由合比定理有xx+y+z=a1+a,yx+y+z=b1+b,zx+y+z=c1+c∴a1+a+b1+b+c1+c=1例2已知m...
First, the evaluation of Example 1 Known xy + z = a, yz + x = b, zx + y = c, find the value of a1 + a + b1 + b + c1 + c. The solution can be deduced from the known x + y + z ≠ 0 by the theorem of proportionality xx + y + z = a1 + a, yx + y + z = b1 + b, zx + y + z = c1 + c∴a1 + a + b1 + b + c1 + c =