题:如图,烧杯的底面积为5分米~2,内装一定量水,此时杯内 A 点的压强为5×10~3帕,若把一木块投入杯中(水不溢出)静止时,杯内 A 点的压强为6×10~3帕,求木块的重?不少的学生都这样分析的,木块在水中漂浮时 G=F_浮,只要求出 F_浮即可.题目已知压强差及底面积(受力面积),即可算出压力差,压力 Question: As shown in the picture, the bottom area of ​​the beaker is 5m2, containing a certain amount of water, and the pressure at point A in the cup is 5×10~3 Pa. If you put a piece of wood into the cup (water does not overflow) At rest, the pressure at point A in the cup is 6×10~3 Pa. The students who ask for the weight of the wooden block are analyzed in this way. When the wooden block floats in the water, G=F_float, as long as the F_float is obtained. Can be known as the pressure difference and bottom area (force area), can calculate the pressure difference, pressure