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在研习各地数学中考题时,偶尔看到了这道题目:有一个运算程序,可以使:a⊕b=n(n为常数)时,得(a+1)⊕b=n+1,a⊕(b+1)=n-2,现在已知1⊕1=2,那么2008⊕2008=____.(2008年广东省茂名市中考数学试卷第15题)这是一道有难度的中考题,学生理解它有一定的困难(仅为个人观点).我在分析该题目时,发现有一个小问题,但不知结论是否正确,现提出,请指正.解因为1⊕1=2,由a⊕b=n(n为常数)时,得(a+1)⊕b=n-1,故2008⊕1=(1+2007)⊕1=2+
Occasionally I see this topic when studying math test questions all over the country: There is an arithmetic program that can make (a + 1) ⊕b = n + 1, a⊕ (b + 1) = n-2, now known 1 ⊕ 1 = 2, then 2008 ⊕ 2008 = _ _ _ _. (Maoming City, Guangdong Province in 2008 exam questions 15) This is a difficult test questions, students Understand it has some difficulties (only personal point of view.) I analyze the subject, I found a small problem, but I do not know the conclusion is correct, it is proposed, please correct. Solution because 1 ⊕ 1 = 2, by a ⊕ b = n (n is a constant), (a + 1) ⊕b = n-1, so 2008⊕1 = (1 + 2007) ⊕1 = 2 +