1问题的提出课堂上,为了更好地说明“赤道上物体受到的万有引力不等于重力,其与支持力的合力提供了物体的向心力”这一问题,笔者选用了教材中的数据进行计算.模型建立:设质量为1 kg的物体静止在赤道上,随地球绕地轴做匀速圆周运动,证明万有引力和支持力的合力提供了物体的向心力.数据来源:地球半径R=6400 km(必修2,第44页第12行),引力常量G=6.67×10~(-11)N·m~2/kg~2(必修2,第40页倒 1 In the classroom, in order to better explain the issue of “the gravitation of the equatorial objects is not equal to gravity, the synergy with the support forces provides the centripetal force of the object,” I chose the data in the textbook to calculate Model establishment: Let a mass of 1 kg be stationary on the equator, and follow the Earth’s uniform circular motion around the ground axis to show that the centripetal force of gravity and support force provide the centripetal force of the object. Source: Earth’s radius R = 6400 km (Compulsory 2 , P. 44, line 12), gravitational constant G = 6.67 × 10 ~ (-11) N · m ~ 2 / kg ~ 2