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[题型一]已知铁粉和硫粉的质量求生成气体的体积 [母题]56g还原铁粉与16g硫粉均匀混合后隔绝空气加热,将反应完全后的固体加入到足量的稀盐酸中,产生的气体在标准状况下所占的体积是 A.22.4L; B.11.2L; C.5.6L; D.28L。 思路探索:由铁跟硫的反应方程式Fe+S=FeS可知:56g铁(1mol)应与32g硫(1mol)恰好完全反应。因此,题中硫粉(16g合0.5mol)不足,铁粉过量,所以,“反应完全后的固体”既有生成的硫化亚铁(0.5mol),又有过量的铁(0.5mol)。这样,此固体中加入足量稀盐酸,将发生如下反应:FeS+2HCl=FeCl2+H2S↑、Fe+
[Type I] Know the quality of iron powder and sulfur powder to generate gas volume [Mouse] 56g reduced iron powder and 16g of sulfur powder are evenly mixed and insulated from air, and the solid after reaction is added to a sufficient amount of rare earth. In hydrochloric acid, the volume of gas produced under standard conditions is A.22.4L; B.11.2L; C.5.6L; D.28L. Exploration of ideas: From the reaction equation of iron and sulfur, Fe+S=FeS, it can be seen that 56 g of iron (1 mol) should react exactly with 32 g of sulfur (1 mol). Therefore, the sulfur powder (16g and 0.5mol) is insufficient and the iron powder is excessive. Therefore, the solid after the completion of the reaction has both the generated ferrous sulfide (0.5 mol) and excess iron (0.5 mol). . In this way, a sufficient amount of dilute hydrochloric acid is added to this solid and the following reaction will take place: FeS+2HCl=FeCl2+H2S↑, Fe+