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设数列{an}满足一阶递推关系:an+1=pan+q.当P≠1且P≠0,q≠0时,数列{an)非等差、等比数列.其通项公式有两种求解思路. 思路1-转化为等比数列求其通项公式在an+1=pan+q中,两边同减去q/1-p得an+1-q/1-p=p(an-q/1-p).
Let the series {an} satisfy the first-order recurrence relation: an+1=pan+q. When P≠1 and P≠0, q≠0, the sequence {an) is non-consecutive and geometric sequence. Its general term formula There are two solution ideas. Idea 1 - Convert to an equal number sequence to find the general term formula in an+1 = pan + q, both sides minus q/1-p get an+1-q/1-p = p (an-q/1-p).