一、定义法例1如图1,M是以A、B为焦点的双曲线x2-y2=2右支上任一点,若点M到点C(3,1)与点B的距离之和为S,则S的取值范围是()(A)[槡26+槡2,+∞)(B)[槡26-2槡2,+∞)(C)[槡26-2槡2,槡26+2槡2)(D)[槡26-槡2,+∞)分析此题的得分率很低,用函数观点求解困难重重.若能利用双曲线的第一定义, First, the definition of law 1 as shown in Figure 1, M is A, B as the focus of the hyperbolic x2-y2 = 2 right branch of any point, if the point M to point C (3,1) and the distance between the points B is S , Then the range of S is () (A) [槡 26 + 槡 2, + ∞) (B) [槡 26-2 槡 2, + ∞) (C) [槡 26-2 槡 2, 槡 26 +2 槡 2) (D) [槡 26- 槡 2, + ∞) Analysis This question scoring rate is very low, difficult to solve with the function point of view.If we can use the first definition of hyperbola,