“:”n。。。n。z,。。。h+h”’··+十H.这是一个很常见的不等式,其证明方法一般采用数学归纳法或利用数列的单调性.下面给出这个不等式的一种新的证法——分段放缩法.证明1”若n为偶数,可设n—Zk（k6N+）_』___,。11则原不等式q=vn-+zr=s+…+。。。、·l,—。、、-。Zk+12h “:”n. . . n. z,. . . h+h”’··++H. This is a very common inequality whose proof method generally adopts mathematical induction or uses the monotonicity of the series. A new proof of this inequality is given below—the segmentation. Scaling. Proof 1" If n is an even number, set n-Zk(k6N+)_』___,. 11 is the original inequality q=vn-+zr=s+...+. . . , l, -. ,, -. Zk+12h