人教版高中《物理》第三册(必修加选修)第48面练习三第3题值得商榷.题目如下:要使氢原子从n=1的状态跃迁到n=3的状态,它所吸收的光子的波长最大是多少?这是不是可见光?《教师教学用书》给出的参考答案如下:解:n=1和n=3两个状态的能量差是△E=E_3-E_1=(-1.51)eV-(-13.6)eV=12.09eV=1.94×10~(-18)J由△E=hv和λ=c/v可知,要使氢原子吸收这样大的能量,光子的波长应为 People’s Education Edition High School “Physics” Volume III (compulsory plus elective) 第 48 面面 Exercise 3 Question 3 is questionable. The title is as follows: To make hydrogen atoms from the state of n = 1 transition to n = 3 state, it absorbed The maximum wavelength of photon is what? This is not visible light? The “teacher’s teaching book” gives the reference answer is as follows: Solution: n = 1 and n = 3 energy difference between the two states is △ E = E_3-E_1 = 1.5) EV - (- 13.6) eV = 12.09 eV = 1.94 × 10 ~ (-18) J From ΔE = hv and λ = c / v we know that for a hydrogen atom to absorb such a large energy, the wavelength of the photon should be