本文拟用另一种方法简捷地证明[1]的例子,与[1]比较有“异曲同工”之妙。并在本文证[1]例子的基础上,得出一个重要方法——增量变换,它是用在不等式变量具有关系a_1≥a_2≥…≥a_(n-t)≥a_n时,引入辅助量a(称为增量),a≥0,令a_1=a+a_1,a_2=a+a_2,…,a_n=a+a_n,有a_1≥a_2≥…≥a_(n-1)≥a_n≥0(常取a_n=0),然后进行论证。往往使问题简化的这样一种变量代换的方法。本文并用此法证明了更为广泛的问题。现给出[1]中例子及其它问题简洁证明如下: This article proposes to use another method to simply prove the example of [1] and compare it with [1]. Based on the example of the paper [1], we obtain an important method—incremental transformation, which is used when the inequality variable has relationship a_1≥a_2≥...≥a_(nt)≥a_n, and introduces the auxiliary amount a ( Referred to as increment), a≥0, let a_1=a+a_1,a_2=a+a_2,...,a_n=a+a_n, there are a_1≥a_2≥...≥a_(n-1)≥a_n≥0(usually Take a_n = 0), and then demonstrate. Such a variable substitution method that often simplifies the problem. This article also uses this method to prove a broader problem. Now give a concise proof of the examples and other problems in [1] as follows: