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初中数学中流行着这样的一个开放性问题:例如图1,点D、E分别在线段AB、AC上,BE、CD相交于点O,AE=AD,要使△ABE≌△ACD,可以添加的一个条件是(请提供尽可能多的添法)说明有学生尝试着添加了“BO=CO”的条件,并做了分析:连接AO,……,不行;连接BC,……,也不行,看来证不了!有教师认同这位学生的想法,并做了简单的点评:证明需结合图形把条件与结论综合起来加以分析,有些条件看似可行,但从逻辑上并不一定行得通.
For example, in Figure 1, points D and E intersect at point AB, AC, BE and CD at point O and AE = AD, respectively. For example, to make ΔABE≌ΔACD, you can add (Please provide as many as possible Tim method) shows that students try to add the conditions of “BO = CO ” and did the analysis: connect AO, ..., no; connect BC, ..., Nor does it seem that the certificate can not! There are teachers agree with the student’s idea, and made a simple comment: Prove the need to combine graphics and conditions and conclusions to be analyzed, some conditions may seem feasible, but not necessarily logically Works well.