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在今年我县的小学数学教师招聘试题中,有一道曾引发广泛关注的题:A、B两地相距20千米,有45人的团队从A地到B地,该团队雇一辆限乘9人的马车,其速度是该团队步行速度的6倍,马车与团队同时从A地出发到B地,马车到B地后,立即回头继续接团队余下人员,就这样往返于团队和B地之间,当团队的所有人员都(运)到B地时,马车共行驶了多少千米?有人认为本题可模仿下述题目的解题方法来做:甲乙两人分别从相距100里的两地同时相对而行,甲每小时走6里,乙每小时走4里。如果甲带一只狗,和甲同时出发,狗以每小时10里的速度向乙奔去,遇到乙后即回头奔向甲,遇到甲后又回头奔向乙…,直到甲乙两人相遇时狗才停住。这只狗共跑了多远?我国著名数学家苏步青的解法是:
In this year's county primary school mathematics teacher recruitment questions, there has been a topic of widespread concern: A, B two 20 km apart, a 45-person team from A to B, the team hired a limited ride 9 carriage, its speed is 6 times the team walking speed, carriage and team at the same time starting from A to B, carriage to B, immediately after the return to continue to take the rest of the team, so from and to the team and B , When the team all the staff (B) to B, the total number of kilometers traveled coach? Some people think that this question can be mimicked by the following problem-solving methods to do: A and B were 100 away from the two At the same time relative to the line, A walk 6 hours per hour, B go 4 miles per hour. If a dog with a, and A starting at the same time, the dog at a rate of 10 miles per hour to Ben Ben ran back after meeting B ran toward A, met A and then headed back to B ... until A and B When the dog stopped. This dog ran a long way? The famous mathematician Su Buqing solution is: