恒成立问题的核心是求出保证等式或不等式恒成立的值,同时还可能涉及参数的求解。在高中数学知识点中,恒成立问题常常与函数有着千丝万缕的联系,要求同学们掌握函数的类型、图像、性质等。解决恒成立问题的方法主要有构造函数、参数分离、数形结合等。本文从恒成立问题的实例出发,对其中的解题方法进行讨论。一、函数构造法例1已知不等式2x-1>m(x2-1)对任意的m∈[-2,2]都成立,求x的取值范围。解析受思维定势影响,在看到本题后,第 The core of the problem of constant set-up is to find the value of guarantee equality or inequality, which may also involve the solution of parameters. Among high school mathematics knowledge points, the problem of constant establishment is often inextricably linked with the function, requiring students to grasp the type of function, image, nature and so on. The main methods to solve the problem of constant establishment are constructor, parameter separation, number combination and so on. This article starts from the example of the problem of constant establishment, and discusses the solution of the problem. First, the function structure Law 1 known inequality 2x-1> m (x2-1) For any m∈ [-2,2] are established, and find the range of x. Analysis by the thinking of the situation, after seeing this question, the first