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现行高三数学复习资料都有这样一道题 :Ａ、Ｂ是抛物线ｙ2 =2 ｐｘ (ｐ 0 )上的两点 ,满足ＯＡ⊥ＯＢ (Ｏ为坐标原点 ) .求证 :直线ＡＢ经过一个定点 .笔者发现该命题可推广如下 :命题 直角顶点在圆锥曲线顶点且内接于圆锥曲线的直角三角形的斜边恒过定点 .下面就椭圆ｘ2ａ2
The current high school math review materials have such a question: A, B is two points on the parabola y2 =2 px (p0), satisfies OA⊥OB (O is the coordinate origin). Proof: Line AB passes a fixed point. The author found The proposition can be generalized as follows: propositional vertices vertices are at the apex of the conic section and the hypotenuse of a right-angled triangle inscribed in a conic section is above the fixed point. The following is an ellipse x2a2.