在平时的解题中,把思路放开一些,对于一道题从多个角度去思考,寻找灵活多变的解法,这样才能开阔视野,提高解题能力.题目已知AD是△ABC的中线,E是AD的中点,F是BE的延长线与AC的交点求证:AF=1/2FC.(初中《几何》第二册第194页第18题)解法1 如图1,过点D作DG∥AC,交BF In the usual problem-solving questions, let the thoughts be opened up, and think about a problem from multiple angles to find flexible solutions so as to broaden your horizons and improve the problem-solving abilities. The topic is known as AD is the midline of △ABC, E is the midpoint of AD, and F is the intersection of BE’s extension line and AC. Proof: AF = 1/2 FC. (Junior Geometry, Volume 2, Page 194, Problem 18) Solution 1 As shown in Figure 1, over point D DG∥AC, Handover BF