在几何题中,我们经常碰到有关比例线段与面积的问题.解决此类问题,需要依据“三角形中同高不等底的面积比等于它们的底的比”. 如图1,点B为线段AC上的一点,O为不在AC所在直线上的一点,则有S△AOB:S△BOC:S△AOC=AB:BC:AC.同样,我们还可以依据“等高不等底的三角形的面积比等于它的底的比”. In geometry problems, we often encounter problems with proportional line segments and areas. To solve such problems, we need to base on the ratio of “the area ratio of the unequal bottom of the triangle equals their bottom”. As shown in Figure 1, point B is A point on line segment AC, where O is not on the straight line of the AC, then there is SΔAOB:SΔBOC:SΔAOC=AB:BC:AC. Similarly, we can also base on the triangle of equal unequal bases. The area ratio is equal to the ratio of its bottom."