论文部分内容阅读
在复习“三角函数”时,老师讲了一道三角题已知sin3α/sin(π/6-3α)=cos3α/cos(π/6-3α)=2~(1/3)(α≠kπ/4,且k∈Z),求tan2α.老师给出的解答:由已知可得
When reviewing the “trigonometric function”, the teacher gave a trigonometric question known as sin3α/sin(π/6-3α)=cos3α/cos(π/6-3α)=2~(1/3)(α≠kπ/ 4, and k∈Z), find tan2α. Answer given by the teacher: Known available