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1,2-双(二溴甲基)苯及4位取代衍生物与反丁烯二腈在N,N-二甲基甲酰胺中反应12 h没有新的产物生成,在同样的条件下,加入碘化钾可使反应发生,主产物是2,3-二氰基萘及其6位取代衍生物,它的产率随加入的碘化钾的量不同而不同.当碘化钾的加入量相当于1,2-双(二溴甲基)苯及4位取代衍生物分子中溴的摩尔数,则1,2-双(二溴甲基)苯及其4位取代衍生物与反丁烯二腈基本作用完毕,反应产物主要是2,3-二氰基萘及其6位取代衍生物,产率87.1%.这个实验事实表明,碘化钾的作用机制不是传统意义上的催化剂而是一个反应试剂.据此,提出了上述反应的机理.
No new products were formed after reaction of 1,2-bis (dibromomethyl) benzene and 4-substituted derivatives with fumaronitrile in N, N-dimethylformamide. Under the same conditions, Addition of potassium iodide can make the reaction, the main product is 2,3-dicyanonaphthalene and its derivatives 6, its yield with the amount of added potassium iodide varies.When the amount of potassium iodide equivalent to 1,2 - bis (dibromomethyl) benzene and 4-substituted derivatives of the number of moles of bromine molecule, the 1,2-bis (dibromomethyl) benzene and its 4-substituted derivatives and fumaronitrile basic role At the end of the reaction, the reaction product was mainly 2,3-dicyanonaphthalene and its 6-substituted derivative in a yield of 87.1%. This experimental fact indicates that the mechanism of action of potassium iodide is not a traditional catalyst but a reagent , Put forward the mechanism of the above reaction.