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煅烧中压汽消耗是我公司能源消耗的重点,如何降低中压汽消耗一直是公司各级领导及管理人员非常重视的问题,近年来实施了多项技术改造、技措项目,也取得了一定成效,为了使指标制定的更合理,现将中压汽消耗理论计算如下,以为来年制定年度消耗指标做参考依据。一物料组分 3、计算条件: 重碱:温度25℃,比容热1.628kJ/(kg.K) 返碱:温度180℃,比容热1.151kJ/(kg.K) 纯碱:温度195℃,比容热1.628kJ/(kg.K) 出气:温度125℃,比容热1.703kJ(kg.K) 蒸气条件: 蒸汽压力:3.20MPa=32.629kgf/cm~2 饱和蒸温度:238.63℃(化工热力学) 蒸汽冷凝潜热:1.770MJ/kg 使用过热蒸汽温度:265℃〔(273+256) 12=265〕 265℃时,蒸汽比热值:1.983KJ/kg℃(纯碱工学) 蒸汽过热温度:265-238.63=26.37℃每公斤过热蒸汽的过热量:1X26.37X1.983÷ 1000=0.052(MJ/kg) 每公斤压力为3.20MPa 过热蒸汽冷凝潜热: 1.770+0.052=1.822(MJ/kg) 4、每吨纯碱需用重碱量 m:kg/t 设煅烧损失率为1% mp=1000X(1+0.01)÷0.5171=1953.2(kg/t) 其中:NaHCO_3=1953.2X0.7218=1409.8(kg/t)
The consumption of calcined medium pressure steam is the key point of our company’s energy consumption. How to reduce the consumption of medium pressure steam has always been the issue that leaders and managers at all levels attach great importance to. In recent years, a number of technical transformation projects and technical measures have been achieved. Effectiveness, in order to make the index more reasonable, now the theory of consumption of medium pressure steam is calculated as follows, to set an annual consumption target for the coming year to make reference. A material component 3, the calculation conditions: heavy base: temperature 25 ℃, specific heat 1.628kJ / (kg.K) back to the base: temperature 180 ℃, specific heat 1.151kJ / (kg.K) soda: temperature 195 ℃ , Specific heat 1.628kJ / (kg.K) Outlet: temperature 125 ℃, specific heat 1.703kJ (kg.K) Steam conditions: steam pressure: 3.20MPa = 32.629kgf / cm ~ 2 saturated steam temperature: 238.63 ℃ Chemical heat) Steam condensing latent heat: 1.770MJ / kg Using superheated steam temperature: 265 ℃ [(273 + 256) 12 = 265〕 265 ℃, steam specific heat value: 1.983KJ / kg ℃ 265-238.63 = 26.37 ℃ Superheat of superheated steam per kilogram: 1X26.37X1.983 ÷ 1000 = 0.052 (MJ / kg) 3.20MPa per kilogram of pressure Superheated steam latent heat of condensation: 1.770 + 0.052 = 1.822 (MJ / kg) 4 , Per tonne of soda need to use heavy alkalinity m: kg / t set calcination loss rate of 1% mp = 1000X (1 +0.01) ÷ 0.5171 = 1953.2 (kg / t) Where: NaHCO_3 = 1953.2X0.7218 = 1409.8 / t)