1引言若偏心受压柱采用对称配筋,进行配筋计算时,对于如何判断大、小偏心,目前有两种说法:1)直接根据受压区高度判断,即,x=N/α1fcb,x≤ξbh0时为大偏心,xξbh0时为小偏心[1]。2)在非对称配筋判别条件的基础上加以补充,认为ηei0·3h0且x≤ξbh0时为大偏心受压,ηei≤0·3h0 1 Introduction If the eccentric compression column with symmetrical reinforcement, reinforcement calculation, how to determine large and small eccentric, there are two versions: 1) directly under the pressure zone height to determine, that is, x = N / α1fcb, x ≤ ξbh0 for large eccentricity, xξbh0 for a small eccentric [1]. 2) On the basis of the criteria of asymmetric reinforcement, it is considered that ηei0 · 3h0 and x≤ξbh0 are large eccentric compression, ηei≤0 · 3h0