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高中《化学》第二册第一章“原电池金属的腐蚀和防护”一节中有2H_2O+O_2+4e=4 OH~-反应式;在“电解和电镀”一节的习题(2),要求学生自已写出在阳极上发生的电极反应方程式为4OH~-—4e=2H_2O+O_2↑;在第三章“铁”一节中有4Fe(OH)_2+2H_2O+O_2=4 Fe(OH)_3的化学方程式。这些散见于各章节中的知识,若能在复习时把它们进行归纳、对比,进而找出它们间的区别和联系(详见下述表格),对学生系统地掌握知识大有
There is 2H_2O+O_2+4e=4 OH~-reaction in the section “Corrosion and Protection of Primary Cell Metals” in Chapter 1 of High School “Chemical” Volume II; Exercises (2) in the section “Electrolysis and Electroplating”, Students are required to write their own equation for the electrode reaction that occurs at the anode as 4OH~—4e=2H_2O+O_2↑; in the third chapter “Iron”, there is 4Fe(OH)_2+2H_2O+O_2=4 Fe(OH). )_3 chemical equation. If the knowledge scattered in each chapter can be summarized and compared during the review, then the differences and connections between them (see the following table for details) can be mastered systematically for students.