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本文提出一种测定1—萘酚的比色分析方法。方法的原理如下。先在盐酸溶液中将1—萘酚亚硝基化。生成的亚硝基萘酚在醋酸缓冲溶液中与钴形成络合物。此络合物在450nm有最大吸收。藉此可测定1—萘酚的含量。如果1—萘酚的含量较低,则可用甲基异丁基酮萃取,然后用光度法测定。苯酚,邻、间甲苯酚及2、4—二甲基苯酚不干扰1—萘酚的测定。对甲苯酚与邻氯苯酚也能生成有色化合物,但其最大吸收波长与1—萘酚不同,故可在470nm测光吸收值以消除干扰。2—萘酚有类似反应,但其络合物的摩尔吸收系数远较1—萘酚为低。故少量2—萘酚的影响可以忽略。
This paper presents a colorimetric assay for the determination of 1-naphthol. The principle of the method is as follows. 1-naphthol is first nitrosated in hydrochloric acid solution. The resulting nitroso-naphtol forms a complex with cobalt in an acetic acid buffer solution. This complex has maximum absorption at 450 nm. By this measure 1-naphthol content. If the 1-naphthol content is lower, it can be extracted with methyl isobutyl ketone, and then measured by spectrophotometry. Phenol, o-, m-cresol and 2,4-dimethylphenol do not interfere with the determination of 1-naphthol. P-cresol and orthochlorophenol can also generate colored compounds, but the maximum absorption wavelength and 1 - naphthol different, it can be measured at 470nm absorbance to eliminate interference. 2-Naphthol has a similar reaction but the molar absorption coefficient of its complex is much lower than that of 1-naphthol. Therefore, a small amount of 2-naphthol can be neglected.