以下两个不等式的原证均是利用代数方法证明的 .现利用三角代换的方法给出新证 ,这种证法 ,不仅通俗易懂 ,而且对变形的技巧要求不高 ,现说明如下 .1　已知实数 a1,b1,c1,求证 :a3b2 - 1+ b3c2 - 1+ c3a2 - 1≥ 932 .(《数学通报》2 0 0 0年第 11期数学问题12 84)证明　因 a The original proofs of the following two inequalities are all proved by using algebraic methods. Now we use the trigonometric substitution method to give new proofs. This kind of proofs is not only easy to understand, but also has low requirements for deformation techniques. 1 Known real numbers a1,b1,c1, verification: a3b2 - 1+ b3c2 - 1+ c3a2 - 1≥ 932. (Mathematics Bulletin, Issue No. 11 of 2001, Mathematical Questions 12 84) Prove that a