导数问题经常出现在压轴题,它在各种考试中的地位不可小觑.本文通过一道“压轴题”解法探究,浅谈一下导数之“不等式证明”的方法运用.题目已知函数f(x)=(x+1)lnx/x-1(x>0且x≠1),(1)讨论函数f(x)的单调性;(2)证明:f(x)>2.一、结论探求初拿到本题,乍一看觉得不难,因为所考查的函数不含参数,避免了分类讨论的繁琐,可是又觉得不会这么简单,因为毕竟处于22 Derivative problems often appear in the finale title, its status in a variety of examinations can not be underestimated .This article through a “finale problem ” method to explore, let’s talk about the derivative “inequality proof ” method. The function f (x) = (x + 1) lnx / x-1 (x> 0 and x ≠ 1), (1) discuss the monotonicity of the function f First, the conclusion to explore the early to get the problem, at first glance is not difficult, because the function of the test without parameters to avoid the tedious classification, but do not think so simple, because after all, at 22