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在pH≈ 6 5及NaAsO2 和Co(NO3 ) 3 ·6H2 O存在下 ,Na2 WO4·2H2 O与Ce(NO3 ) 3 ·6H2 O反应 ,得到了Na9[CeW10 O3 6]·34H2 O单晶 .用元素分析及X射线单晶衍射法确定了其组成与结构 ,晶体学数据为 :a =1 30 10 (5 )nm ,b =1 30 72 (5 )nm ,c=1 996 2 (8)nm ,α=10 1 0 73(7)° ,β=10 4 4 11(5 )° ,γ =90 4 73(4)°,V =3 2 2 1(2 )nm3 ,空间群P1- ,V =3 2 11(2 )nm3 ,Z =4 ,最终R因子 [I>2σ(I) ]R1=0 0 4 2 4 ,wR2 =0 0 5 4 9,R因子 (全部数据 )R1=0 135 7,wR2=0 0 80 8.[CeW10 O3 6]9-具有D4d对称性 .
The reaction of Na2 WO4 · 2H2O with Ce (NO3) 3 · 6H2O in the presence of pH≈65 and NaAsO2 and Co (NO3) 3 · 6H2 O yielded Na9 [CeW10 O3 6] · 34H2 O single crystals. The results of elemental analysis and X-ray single crystal diffraction show that the composition and structure of the crystal are as follows: a = 1 30 10 (5) nm, b = 1 30 72 (5) nm, c = 1 996 2 , α = 10 1 0 73 (7) °, β = 10 4 4 11 (5) °, γ = 90 4 73 (4) °, V = 3 2 2 1 = 3 2 11 (2) nm3, Z = 4, final R factor [I> 2σ (I)] R1 = 0 0 4 2 4, wR2 = 0 0 5 4 9, R factor (all data) 7, wR2 = 0 0 80 8. [CeW10 O3 6] 9- has D4d symmetry.