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采用热膨胀法对Zr-1Nb-0.01Cu合金在不同升温速率下α_(Zr)→α_(Zr)+β_(Zr)相转变动力学进行了研究。结果表明,α_(Zr)→α_(Zr)+β_(Zr)相转变起始温度与升温速率之间的关系为:Tα→α+β=744.4+9.4ln(R H),升温速率对合金相转变温度的影响要小于E110合金;结合JMA方程计算得到α_(Zr)→α_(Zr)+β_(Zr)相转变的激活能为149.1 kJ/mol,低于Zr-4和M5合金的相转变激活能。根据合金相转变动力学曲线,给出了合金连续升温过程α_(Zr)→α_(Zr)+β_(Zr)相转变的CHT连续升温相转变图。
The kinetics of transformation of α-Zr-α-Zr-β-Zr phase at different heating rates was investigated by thermal expansion method. The results show that the relationship between the initial temperature and the heating rate of α Zr (Zr) + β Zr transformation is: Tα → α + β = 744.4 + 9.4ln (RH) The effect of transformation temperature is smaller than that of E110 alloy. The activation energy of α Zr (Zr) + β Zr transformation calculated by JMA equation is 149.1 kJ / mol, which is lower than that of Zr-4 and M5 alloys Activate energy. According to the kinetics curve of alloy phase transformation, the continuous temperature-rising phase transition of α-Zr → α-Zr + β-Zr phase was given.