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由2-溴代-2,3-二甲基丁烷与溴化苯基鎂在二溴化鈷存在時所起的反應得到如下產物:2,3-二甲基丁烷(35％),2,3-二甲基丁烯-1(31％)及2,3-二甲基丁烯-2(約2％)。由1-氯代-1-甲基環己烷同溴化甲基鎂或溴化異丙基鎂在二溴化鈷存在時的反應得到甲基環己烷,1-甲基環己烯及次甲基環己烷的混合物。此外,還得到少量的高沸點產物,大概为一雙聚合物。在不飽和的單體中,有相當一部分为次甲基環己烷。用鹼處理2-溴代-2,3-二甲基丁烷所得到的烯烴中合有79％的2,3-二甲基丁烯-2和21％的2,3-二甲基丁烯-1。1-氯代-1-甲基環己烷與鹼起消除作用時則只生成1-甲基環己烯。自由烷基在液相中的歧化作用可能为一雙分子反應,烷基分子中的α-碳原子土所具有的氫原子的數目對於烧烴形成的定向表現一定的影響。
The reaction from 2-bromo-2,3-dimethylbutane with phenylmagnesium bromide in the presence of cobalt dibromide gave the product 2,3-dimethylbutane (35%), 2,3-dimethylbutene-1 (31%) and 2,3-dimethylbutene-2 (about 2%). The reaction of 1-chloro-1-methylcyclohexane with methylmagnesium bromide or isopropylmagnesium bromide in the presence of cobalt dibromide gives methylcyclohexane, 1-methylcyclohexene and Methylcyclohexane mixture. In addition, you get a small amount of high-boiling product, roughly a double polymer. In the unsaturated monomer, a considerable part of the methylcyclohexane. The alkenes obtained by treating 2-bromo-2,3-dimethylbutane with a base combined 79% of 2,3-dimethylbutene-2 and 21% of 2,3-dimethylbutane Ene-1.1-chloro-1-methylcyclohexane with base only eliminates 1-methylcyclohexene. The disproportionation of free alkyl in the liquid phase may be a bimolecular reaction, and the number of hydrogen atoms in the α-carbon atom in the alkyl molecule has some influence on the orientation performance of the formation of the combustion hydrocarbon.