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2011年浙江省初中毕业生学业考试(衢州卷)第21题是一道由浙教版数学八年级下册第二章一元二次方程的应用36页的例题改编而成的.这是一道很普通的常规应用题,令人意想不到的是考生的解法多达几十种,可谓是解应用题中的一大奇观.下面是笔者在阅卷过程中整理出来的一些比较典型的解法和启示.一、题目某花圃用花盆培育某种花苗,经过试验发现每盆的盈利与每盆的株数构成一定的关系.每盆植入3株时,平均单株盈利3元;以同样的栽培条件,若每盆增加1株,平均单株盈利就减少0.5元.要使每盆的盈利达到10元,每盆应该植多少株?小明的解法如下:解设每盆花苗增加x株,则每盆花苗有(x+3)株,平均单株盈利为(3-0.5x)元.
2011 Zhejiang Province junior high school graduates academic exam (Quzhou Volume) Question No. 21 is a Zhejiao Pupil eighth grade eighth chapter second quadratic equation application page 36 examples adapted from. This is a very common Of the routine application questions, it is unexpected that the examinee as many as dozens of solutions, can be described as a solution to the problem of a big spectacle. The following is the author in the marking process sorted out some of the more typical solutions and enlightenment .A, Subjects flowerbed nursery flower seedlings with a pot, after testing found that each pot’s profit and the number of pots per pot constitute a certain relationship between each pot implanted 3, the average profit of 3 yuan per plant; the same cultivation conditions, if An increase of 1 per pot, the average profit per plant on the reduction of 0.5 yuan. To make each pot profit of 10 yuan, how many plants should be planted per pot? Xiao Ming’s solution is as follows: There are (x +3) strains, the average profit per plant (3-0.5x) dollars.