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关于e和π这两个重要的超越数,有这样一个美妙的不等式成立:eπ>πe．事实上,因为对数函数lnx是单调递增函
With regard to the two important transcendental numbers of e and π, there is such a wonderful inequality that holds: eπ>πe. In fact, because the logarithmic function lnx is a monotonically increasing letter