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抛物线y=ax~2+bx+c(a≠O)当△=b~2-4ac>0时,它与x轴有两个交点,这两个交点和顶点的连线构成等腰三角形.我们提供下列三个计算公式:
The parabola y=ax~2+bx+c(a≠O) When △=b~2-4ac>0, it has two intersections with the x-axis. The line connecting the two points and the vertex constitutes an isosceles triangle. We provide the following three calculation formulas: