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将化学式进行一定的转换,将比较复杂的问题转化为比较简单的问题,给我们的解题带来许多方便之处,以下以几组题目示例说明:例1.下列各组物质中各有两组分,两组分各取1 mol,在足量氧气中燃烧,两者耗氧量不相同的是()A.乙烯和乙醇B.乙炔和乙醛C.乙烷和乙酸甲酯(C3H6O2)D.乙醇和乙酸解析:将选项中的每一种成分的化学式改写如下
Some chemical formula conversion, the more complex problems into simpler problems, to our problem-solving many conveniences, the following examples to illustrate several groups: Example 1. Each of the following groups of two Components, the two components each take 1 mol, burning in sufficient oxygen, both oxygen consumption is not the same () A. Ethylene and ethanol B. acetylene and acetaldehyde C. ethane and methyl acetate (C3H6O2 ) D. Ethanol and Acetic Acid Resolution: The chemical formulas of each of the components in the options are rewritten as follows