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一、选择题1.(江苏生物卷-2)下列有关神经兴奋的叙述,正确的是()A.静息状态时神经元的细胞膜内外没有离子进出B.组织液中Na~+浓度增大,则神经元的静息电位减小C.突触间隙中的神经递质经主动运输穿过突触后膜而传递兴奋D.神经纤维接受刺激产生的兴奋以电信号的形式传导解题思路:形成静息电位主要是由于细胞内的K~+离子外流,呈现内负外正状态;当组织液中Na~+
First, the multiple-choice questions 1. (Jiangsu biological volume -2) The following narrative about nerve excitement, the correct is () A. Resting state neurons inside and outside the cell membrane out of the ion B. Na + concentration in tissue fluid increased, The resting potential of neurons decreases C. The neurotransmitter in the synaptic cleft passes through the postsynaptic membrane and delivers excitement through active transport D. The excitation of nerve fibers receiving stimuli is transmitted in the form of an electrical signal. Problem-solving: The formation of resting potential is mainly due to the intracellular K ~ + ion outflow, showing negative internal state; when the tissue fluid Na ~ +