近年来,部分地市的数学中考命题中出现了如下试题:若(4b)~(1/a+b)与(3a+b)~(1/2)是同类二次根式,则 a,b 的值是( )。A.a=0,b=2B.a=1,b=1C.a=0,b=2或 a=1,b=1D.a=2,b=0此题所给的答案是 A 据此,其解法为:因(4b)~(1/a+b)=2(b)~(1/a+b),由a+b=2,b=3a+b,解得 a=0,b=2.选 A.解法的依据显然是同类二次根式的定义:几个二次根式化成最简二次根 In recent years, the following questions have appeared in the examination propositions of mathematics in some cities: If (4b)~(1/a+b) and (3a+b)~(1/2) are the same type of secondary roots, then a,b The value is (). Aa=0,b=2B.a=1,b=1C.a=0,b=2 or a=1,b=1D.a=2,b=0 The answer to this question is A. According to this, The solution is: because (4b) ~ (1/a + b) = 2 (b) ~ (1/a + b), from a + b = 2, b = 3a + b, the solution a = 0, b = 2. Select A. The basis of the solution is obviously the definition of the same kind of secondary root: several secondary roots into the simplest secondary roots