在一元二次方程ax2+bx+c=0(a≠0)中,常常隐含着a+b+c=0,此时方程的根究竟有什么特征呢?下面我们来研究这个问题。首先,为了能更清楚地看到方程与系数的关系,我们可以先由a+b+c=0,得b=-(a+c),代入方程消去b,得ax2-(a+c)x+c=0,ax(x-1)-c(x-1)=0,(x-1)(ax-c)=0,哈,原来方程的两根 In the quadratic equation ax2+bx+c=0 (a≠0), a+b+c=0 is usually implied. What is the characteristic of the root of the equation at this time? Let’s study this problem. First of all, in order to more clearly see the relationship between the equation and the coefficient, we can first get a+b+c=0, get b=-(a+c), substitute it into the equation to eliminate b, get ax2-(a+c) x+c=0, ax(x-1)-c(x-1)=0, (x-1)(ax-c)=0, ha, two roots of the original equation